Chapter 3 · Visualization 5 of 6 · Section 3.5

Pinch-off Voltage and Control From Terminal C

Fix the gate and use VCB as the control. The inversion charge falls almost linearly, would reach zero at the pinch-off voltage VP, and then decays exponentially instead.

Inversion charge versus VCB at fixed VGB (Fig. 3.16); amber line: VP

Pinch-off voltage versus VGB (dot: your VGB)

What to look for

VP = ψsa(VGB) − φ0, ψsa = (−γ/2 + √(γ²/4 + VGB − VFB))²

  • Linear axis: in strong inversion |Q′I| falls almost linearly with VCB; extrapolated to zero it gives VP.
  • Log axis: past VP the charge does not vanish; it falls by 10× per 60 mV of VCB (slope 1/φt, not 1/nφt).
  • VP grows with VGB with slope about 1/n: this VP is the one used in Chapter 4 for saturation.

Try this

  1. At VGB = 2 V, read VP. Set VCB = VP: what fraction of the VCB = 0 charge is left?
  2. Switch to log scale and measure how much VCB reduces the charge by one decade in weak inversion.
  3. Find the VGB at which VP = 0. What is that voltage called?
  4. Double tox. Does the slope of VP versus VGB increase or decrease? Relate it to n.