1This week's plan
Datta Part B, Chapter 17: Contact-ing Schrödinger (wave equation, matrix form, tight binding, graphene).
Colab notebook week12_tight_binding_C6.ipynb: Part 1 follows the lecture, Part 2 is the C6 lab (B1–B4) and the problem clinic.
Quiz (aim for 8/10), practice problems, and prepare a two-minute explanation for Block D of C6.
By the end of the week you should be able to
- Obtain the Schrödinger equation from E(p) with E → iħ∂/∂t, p → −iħ∇ and add a potential U(r).
- Explain affinity vs ionization levels, the charging energy U₀ and when the self-consistent field works.
- Write EΨ = HΨ in a basis; know N = n × b and the overlap matrix S.
- Fit t = −ħ²/2ma², ε = Ec − 2t (1D) or Ec − 4t (2D); put U(x) on the diagonal and B into Peierls phases.
- Derive graphene's E = ε ± |h₀(k)|, its two valleys and the Dirac velocity.
2Key ideas in five sentences
- Wave equation from E(p). Replacing E and p by operators turns E = p²/2m + U into iħ∂ψ/∂t = Hopψ; plane waves eik·r − iEt/ħ have p = ħk.
- Interactions. An electron added (affinity) or removed (ionization) sees different potentials, separated by U₀; the SCF approximation uses one average potential and fails when U₀ is large.
- Matrix form. In any basis the Schrödinger equation is E[S]{ψ} = [H]{ψ}; with localized orbitals (tight binding) H is sparse, of size atoms × orbitals per atom.
- Bands from lattices. Translational invariance gives E(k) = ΣmHnmeik(m−n)a: a cosine for a chain, which matches the parabola near the band bottom when t = −ħ²/2ma².
- Graphene. Two atoms per unit cell give a 2 × 2 h(k) and E = ε ± |h₀|; h₀ vanishes at two valleys where the bands touch in Dirac cones with v₀ ≈ 10⁶ m/s.
3Equation sheet
4Physics refresher: waves, eigenvalues, matrices
Clamp a wave at x = 0 and L: only sin(nπx/L) survives, so k = nπ/L and En = ħ²π²n²/2mL². For L = 10 nm and m = m₀, E₁ = 3.76 meV; it scales as 1/(mL²).
H = H† has N real eigenvalues and orthonormal eigenvectors. In numpy: E, V = np.linalg.eigh(H); column V[:, n] is the n-th state, |V[j, n]|² its probability on site j.
Why the second derivative becomes (ψn+1 − 2ψn + ψn−1)/a²
Taylor: ψ(x ± a) = ψ ± aψ′ + (a²/2)ψ″ ± …; adding the two removes ψ′ and gives ψ″ ≈ [ψ(x + a) − 2ψ(x) + ψ(x − a)]/a². Multiply by −ħ²/2m: diagonal −2t, neighbours t, with t = −ħ²/2ma².Why an open chain has ε + 2t cos(nπ/(N + 1))
Try ψj = sin(jka). Row j of HΨ gives εψj + t(ψj+1 + ψj−1) = (ε + 2t cos ka)ψj. The ends need ψ0 = ψN+1 = 0, so k(N + 1)a = nπ.Ring vs open chain
A ring adds H1N = HN1 = t; Bloch waves eijka with k = 2πm/Na; ±k have the same energy, so levels come in pairs.5Glossary
| Term | Meaning |
|---|---|
| Hamiltonian H | The operator (or matrix) whose eigenvalues are the allowed energies. |
| Basis function um | A known function (often an atomic orbital) used to expand ψ. |
| Overlap matrix S | Snm = ∫un*um; the identity for an orthogonal basis. |
| Tight binding | Matrix H in a localized basis, with on-site ε and hopping t to neighbours. |
| Charging energy U₀ | The difference between affinity and ionization levels: the cost of one extra electron. |
| SCF | Self-consistent field: each electron moves in an average potential from all others. |
| Peierls phase | t → t eiqA·a/ħ: how a magnetic field enters a tight-binding H. |
| Valley, Dirac cone | Points in k where graphene's bands touch, with E linear in |k − K|. |
6Calculators
Tight-binding parameters from m and a
Eigenvalues of a chain
Graphene near a valley
7Self-check quiz
Click an answer: you get instant feedback. Score: 0 / 0
8Practice problems
ħ²/2m₀ = 0.0381 eV·nm²; ħ = 6.582 × 10⁻¹⁶ eV·s; Φ₀ = h/q = 4.136 × 10⁻¹⁵ T·m².
m = m₀ and a = 0.25 nm. Find t, ε − Ec and the band width of a 1D chain.
Solution
t = −0.0381/0.0625 = −0.610 eV; ε − Ec = −2t = +1.22 eV; band width 4|t| = 2.44 eV.GaAs (m = 0.067m₀) on a grid with a = 1 nm: t and band width?
Solution
t = −0.0381/0.067 = −0.569 eV; 4|t| = 2.27 eV. Grids for low-mass materials can be coarser.ε = 0, t = −1 eV, periodic boundary. List the eigenvalues.
Hint
k = 2πm/6a.Solution
2t cos(πm/3): −2, −1, −1, +1, +1, +2 eV; the ±k pairs are degenerate.ε = −10 eV, t = −3 eV, s = 0.2. Bonding and antibonding energies?
Solution
(ε + t)/(1 + s) = −13/1.2 = −10.83 eV; (ε − t)/(1 − s) = −7/0.8 = −8.75 eV. With s ≠ 0 the antibonding level rises more than the bonding level falls.ε = 0, t = −1 eV. Lowest and highest eigenvalues? Is the band width 4|t|?
Solution
2t cos(π/11) = −1.919 eV and +1.919 eV; the finite chain spans 3.84 eV, approaching 4|t| as N → ∞.A silicon nanowire of 2000 atoms in an sp³s* basis (5 orbitals per atom), with spin. Size of H?
Solution
N = n × b = 2000 × 5 × 2 = 20 000; a dense matrix would have 4 × 10⁸ entries, so sparsity matters.|t| = 2.7 eV, acc = 0.142 nm. Find v₀ and the energy 0.1 nm⁻¹ from a valley.
Solution
v₀ = 1.5 × 0.142 nm × 2.7 eV/ħ = 8.74 × 10⁵ m/s; ħv₀ × 0.1 nm⁻¹ = 57.5 meV.A ring of diameter 100 nm. Which B threads one flux quantum? What happens to its levels as B goes from 0 to twice that?
Solution
B = Φ₀/(π × (50 nm)²) = 0.53 T. The spectrum is periodic in Φ with period Φ₀: at 2Φ₀ it is back to the B = 0 spectrum.Show the 2D square lattice band runs from Ec to Ec + 8|t| and near the bottom E ≈ Ec + ħ²k²/2m.
Hint
cos x ≈ 1 − x²/2.Solution
With ε = Ec − 4t and t < 0: k = 0 gives Ec, (π/a, π/a) gives Ec − 8t = Ec + 8|t|. Expanding: E ≈ ε + 4t − t(kₓ² + ky²)a² = Ec + ħ²k²/2m.9Common mistakes
10Explore
Files are in the course folder (course_materials).
Mini-investigations (15 min each)
- In the chain widget, make N = 40 and add the linear field. Which states are localized near the low-potential end, and why does the spacing become uneven?
- In the lattice widget, find the energy at which the square-lattice contours become a square (the "van Hove" energy). What is special about the density of states there?
- In the notebook, compute armchair ribbon gaps for N = 3p, 3p + 1, 3p + 2 up to N = 30 and fit gap ∝ 1/width for the two gapped families.
11Can I…?
Tick what you can do without notes. Your ticks are saved in this browser.
12Looking ahead: Week 13
The NEGF method (Datta Part B, Ch. 18): the H of this week meets the contacts through self-energies Σ.
- How does connecting a level to a contact broaden it?
- What are GR = [EI − H − Σ]⁻¹, the spectral function and the transmission?
- How do we include scattering ("dephasing") as one more contact?